LeetCode Ruby No.101 symmetric-tree
类比 No.100 判断相同的树
# Definition for a binary tree node.
# class TreeNode
# attr_accessor :val, :left, :right
# def initialize(val)
# @val = val
# @left, @right = nil, nil
# end
# end
# @param {TreeNode} root
# @return {Boolean}
def is_symmetric(root)
return true if root.nil?
compare_func(root.left, root.right)
end
def compare_func(p, q)
return true if p.nil? && q.nil?
if p && q && (p.val == q.val)
compare_func(p.left, q.right) && compare_func(p.right, q.left)
else
false
end
end